Synthesis and crystal structure of the mixed-valent TeIV/VI compound PbTe3O8.

Abstract

The crystal structure of the mixed-valent compound PbTe3O8(= PbIITeIV2TeVIO8), lead(II) bis-[oxidotellurate(IV)] tellurate(VI), is isotypic with that of SrTe3O8. It comprises 1∞[Te3O8]2- chains sharing O atoms to form a framework with two types of square channels extending parallel to [001]. The smaller channels (diameter ∼4 Å) are occupied by 12-coordinate PbII atoms in the centre of the channel, whereas the slightly larger channels (diameter ∼4.5 Å) accommodate the stereoactive 5s2 electron lone pair of TeIV.

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